The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm, is incident on it. The band gap in (eV) for the semiconductor is:

Question

The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm, is incident on it. The band gap in (eV) for the semiconductor is: (A) 1.1 eV (B) 2.5 eV (C) 0.5 eV (D) 0.7 eV

Tardigrade Admin · Accepted Answer

Eg=h v =(h c/λ)=((6.63×10-34×3×108/2480×10-9×1.6×10-19))eV =0.5 eV

Q. The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than $2480 nm$ , is incident on it. The band gap in ( $e V$ ) for the semiconductor is:

$1.1 e V$

$2.5 e V$

$0.5 e V$

$0.7 e V$

$E_{g} = h v$
$= \frac{h c}{λ} = (\frac{6.63 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{2480 \times 1 0 ^{- 9} \times 1.6 \times 1 0 ^{- 19}}) e V$
$= 0.5 e V$

Q. The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480nm, is incident on it. The band gap in (eV) for the semiconductor is:

1.1eV

2.5eV

0.5eV

0.7eV