The electric potential at the centre of two concentric half rings of radii R1 and R2, having same linear charge density λ is :

Question

The electric potential at the centre of two concentric half rings of radii R1 and R2, having same linear charge density λ is : (A) (2 λ/ϵ0) (B) (λ/2 ϵ0) (C) (λ/4 ϵ0) (D) (λ/ϵ0)

Tardigrade Admin · Accepted Answer

Potential at centre V=((λ ⋅ π R2)/4 π ε0 R2)+((λ ⋅ π R1)/4 π ε0 R1) =(λ/2 ε0)

Q. The electric potential at the centre of two concentric half rings of radii $R_{1}$ and $R_{2}$ , having same linear charge density $λ$ is :

$\frac{2 λ}{ϵ _{0}}$

$\frac{λ}{2 ϵ _{0}}$

$\frac{λ}{4 ϵ _{0}}$

$\frac{λ}{ϵ _{0}}$

Potential at centre
$V = \frac{( λ \cdot π R _{2} )}{4 π ε _{0} R _{2}} + \frac{( λ \cdot π R _{1} )}{4 π ε _{0} R _{1}}$
$= \frac{λ}{2 ε _{0}}$

Q. The electric potential at the centre of two concentric half rings of radii R1​ and R2​, having same linear charge density λ is :

ϵ0​2λ​

2ϵ0​λ​

4ϵ0​λ​

ϵ0​λ​