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Physics
The electric potential at the centre of two concentric half rings of radii R1 and R2, having same linear charge density λ is :
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Q. The electric potential at the centre of two concentric half rings of radii $R_1$ and $R_2$, having same linear charge density $\lambda$ is :
JEE Main
JEE Main 2023
Electrostatic Potential and Capacitance
A
$\frac{2 \lambda}{\epsilon_0}$
17%
B
$\frac{\lambda}{2 \epsilon_0}$
47%
C
$\frac{\lambda}{4 \epsilon_0}$
7%
D
$\frac{\lambda}{\epsilon_0}$
29%
Solution:
Potential at centre
$ V=\frac{\left(\lambda \cdot \pi R_2\right)}{4 \pi \varepsilon_0 R_2}+\frac{\left(\lambda \cdot \pi R_1\right)}{4 \pi \varepsilon_0 R_1} $
$=\frac{\lambda}{2 \varepsilon_0}$