The electric force between two charges each equal to 3 μ C, when placed in vacuum is 12 N, the force between them, if the charges are embedded in a dielectric of constant 6 will be

Question

The electric force between two charges each equal to 3 μ C, when placed in vacuum is 12 N, the force between them, if the charges are embedded in a dielectric of constant 6 will be (A) 36 N (B) 18 N (C) 2 N (D) 1 N

Tardigrade Admin · Accepted Answer

Force acting between the charges placed in vacuum F 0=16 N Dielectric constant of medium K =8 Force acting between the charges placed in medium Fm=(F0/K) ⇒ Fm=(16/8)=2 N

Q. The electric force between two charges each equal to $3 μ C$ , when placed in vacuum is $12 N$ , the force between them, if the charges are embedded in a dielectric of constant $6$ will be

36 N

18 N

2 N

1 N

Force acting between the charges placed in vacuum $F_{0} = 16 N$
Dielectric constant of medium $K = 8$ Force acting between the charges placed in medium $F_{m} = \frac{F _{0}}{K}$
$< b r / >\Rightarrow F_{m} = \frac{16}{8} = 2 N < b r / >$

Q. The electric force between two charges each equal to 3μC, when placed in vacuum is 12N, the force between them, if the charges are embedded in a dielectric of constant 6 will be

36 N

18 N

2 N

1 N

Force acting between the charges placed in vacuum F0​=16N Dielectric constant of medium K=8 Force acting between the charges placed in medium Fm​=KF0​​ <br/>⇒Fm​=816​=2N<br/>

Q. The electric force between two charges each equal to $3 μ C$ , when placed in vacuum is $12 N$ , the force between them, if the charges are embedded in a dielectric of constant $6$ will be

Force acting between the charges placed in vacuum $F_{0} = 16 N$
Dielectric constant of medium $K = 8$ Force acting between the charges placed in medium $F_{m} = \frac{F _{0}}{K}$
$< b r / >\Rightarrow F_{m} = \frac{16}{8} = 2 N < b r / >$