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  4. The electric force between two charges each equal to 3 μ C, when placed in vacuum is 12 N, the force between them, if the charges are embedded in a dielectric of constant 6 will be

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Q. The electric force between two charges each equal to $3\,\mu C$, when placed in vacuum is $12\,N$, the force between them, if the charges are embedded in a dielectric of constant $6$ will be

Electrostatic Potential and Capacitance

Solution:

Force acting between the charges placed in vacuum $F _{0}=16 N$
Dielectric constant of medium $K =8$ Force acting between the charges placed in medium $F_{m}=\frac{F_{0}}{K}$
$
\Rightarrow F_{m}=\frac{16}{8}=2 N
$