The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q1= - 14 nc, q2 = 78.85 nC, q3 = - 56 nC)

Question

The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q1= - 14 nc, q2 = 78.85 nC, q3 = - 56 nC) (A) 103 Nm2C-1  (B) 103 CN-1m-2  (C) 6.32 × 103 Nm2C-1 (D) 6.32 × 103 CN-1m-2

Tardigrade Admin · Accepted Answer

Electric flux =(q/ε0) =((-14+7885-56) × 10-9/885 × 10-12)=(885 × 10-9/885 × 10-12) =1000 Nm 2 C -1

Q. The electric flux for Gaussian surface A that enclose the charged particles in free space is
(given $q_{1} = - 14 n c, q_{2} = 78.85 n C, q_{3} = - 56 n C$ )

$1 0^{3} N m^{2} C^{- 1}$

$1 0^{3} C N^{- 1} m^{- 2}$

$6.32 \times 1 0^{3} N m^{2} C^{- 1}$

$6.32 \times 1 0^{3} C N^{- 1} m^{- 2}$

Electric flux $= \frac{q}{ε _{0}}$
$= \frac{( - 14 + 7885 - 56 ) \times 1 0 ^{- 9}}{885 \times 1 0 ^{- 12}} = \frac{885 \times 1 0 ^{- 9}}{885 \times 1 0 ^{- 12}}$
$= 1000 N m^{2} C^{- 1}$

Q. The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q1​=−14nc,q2​=78.85nC,q3​=−56nC)

103Nm2C−1

103CN−1m−2

6.32×103Nm2C−1

6.32×103CN−1m−2