The electric field that can balance a charged particle of mass 3.2 × 10-27 kg is (Given that the charge on the particle is 1.6 × 10-19 C)

Question

The electric field that can balance a charged particle of mass 3.2 × 10-27 kg is (Given that the charge on the particle is 1.6 × 10-19 C) (A) 19.6 × 10-8 N C-1 (B) 20 × 10-6 N C-1 (C) 19.6 × 108 N C-1 (D) 20 × 106 N C-1

Tardigrade Admin · Accepted Answer

Here, m = 3.2 × 10-27 kg, e = 1.6 × 10-19 C, g=9.8 m s-2 As E=(F/q)=(mg/e) =(3.2×10-27×9.8/1.6×10-19) =19.6×10-8 N C-1

Q. The electric field that can balance a charged particle of mass $3.2 \times 1 0^{- 27} k g$ is (Given that the charge on the particle is $1.6 \times 1 0^{- 19} C$ )

$19.6 \times 1 0^{- 8} N C^{- 1}$

$20 \times 1 0^{- 6} N C^{- 1}$

$19.6 \times 1 0^{8} N C^{- 1}$

$20 \times 1 0^{6} N C^{- 1}$

Here, $m = 3.2 \times 1 0^{- 27} k g$ , $e = 1.6 \times 1 0^{- 19} C$ , $g = 9.8 m s^{- 2}$
As $E = \frac{F}{q} = \frac{m g}{e}$
$= \frac{3.2 \times 1 0 ^{- 27} \times 9.8}{1.6 \times 1 0 ^{- 19}}$
$= 19.6 \times 1 0^{- 8} N C^{- 1}$

Q. The electric field that can balance a charged particle of mass 3.2×10−27kg is (Given that the charge on the particle is 1.6×10−19C)

19.6×10−8NC−1

20×10−6NC−1

19.6×108NC−1

20×106NC−1