The electric field lines on the left have twice the separation on those on the right as shown in figure. If the magnitude of the field at A is 40 Vm-1, what is the force on 20 μ C charge kept at B?

Question

The electric field lines on the left have twice the separation on those on the right as shown in figure. If the magnitude of the field at A is 40 Vm-1, what is the force on 20 μ C charge kept at B? (A) 4 × 10-4 Vm-1 (B) 8 × 10-4 Vm-1 (C) 16 × 10-4 Vm-1 (D) 1 × 10-4 Vm-1

Tardigrade Admin · Accepted Answer

We know that F = qE =20 × 20 × 10-6 =4 × 10-4 V / m-1

Q. The electric field lines on the left have twice the separation on those on the right as shown in figure. If the magnitude of the field at $A$ is $40 V m^{- 1}$ , what is the force on $20 μ C$ charge kept at $B$ ?

$4 \times 1 0^{- 4} V m^{- 1}$

$8 \times 1 0^{- 4} V m^{- 1}$

$16 \times 1 0^{- 4} V m^{- 1}$

$1 \times 1 0^{- 4} V m^{- 1}$

We know that
$F = qE = 20 \times 20 \times 1 0^{- 6}$
$= 4 \times 1 0^{- 4} V / m^{- 1}$

Q. The electric field lines on the left have twice the separation on those on the right as shown in figure. If the magnitude of the field at A is 40Vm−1, what is the force on 20μC charge kept at B?

4×10−4Vm−1

8×10−4Vm−1

16×10−4Vm−1

1×10−4Vm−1