The electric field intensity at a point near and outside the surface of a charged conductor of any shape is ‘E1’. The electric field intensity due to uniformly charged infinite thin plane sheet is ‘E2’. The relation between ‘E1’ and ‘E2’ is

Question

The electric field intensity at a point near and outside the surface of a charged conductor of any shape is ‘E1’. The electric field intensity due to uniformly charged infinite thin plane sheet is ‘E2’. The relation between ‘E1’ and ‘E2’ is (A) 2E1 = E2 (B) E1 = E2 (C) E1 = 2E2 (D) E1 = 4E2

Tardigrade Admin · Accepted Answer

Electric field intensity at a point near and outside the surface of any charged conductor is given by

E_{1} = \frac{σ}{ε _{0}} .. (i)

where,

σ

is charge density (charge per unit area) at a point.
Electric field intensity due to uniformly charged infinite thin plane sheet is given by

E_{2} = \frac{σ}{2 ε _{0}} .. (ii)

From Eqs. (i) and (ii), we have

E_{1} = \frac{2}{2} \times \frac{σ}{ε _{0}} = 2 \times E_{2} \Rightarrow E_{1} = 2 E_{2}

Q. The electric field intensity at a point near and outside the surface of a charged conductor of any shape is ‘ $E_{1}$ ’. The electric field intensity due to uniformly charged infinite thin plane sheet is ‘ $E_{2}$ ’. The relation between ‘ $E_{1}$ ’ and ‘ $E_{2}$ ’ is

$2 E_{1} = E_{2}$

$E_{1} = E_{2}$

$E_{1} = 2 E_{2}$

$E_{1} = 4 E_{2}$

Q. The electric field intensity at a point near and outside the surface of a charged conductor of any shape is ‘E1​’. The electric field intensity due to uniformly charged infinite thin plane sheet is ‘E2​’. The relation between ‘E1​’ and ‘E2​’ is

2E1​=E2​

E1​=E2​

E1​=2E2​

E1​=4E2​

Q. The electric field intensity at a point near and outside the surface of a charged conductor of any shape is ‘ $E_{1}$ ’. The electric field intensity due to uniformly charged infinite thin plane sheet is ‘ $E_{2}$ ’. The relation between ‘ $E_{1}$ ’ and ‘ $E_{2}$ ’ is

$2 E_{1} = E_{2}$

$E_{1} = E_{2}$

$E_{1} = 2 E_{2}$

$E_{1} = 4 E_{2}$