The electric field in a region of space is given by, vecE = Eo hati + 2 Eo hatj where E0 = 100 N/C. The flux of this field through a circular surface of radius 0.02 m parallel to the Y-Z plane is nearly :

Question

The electric field in a region of space is given by, vecE = Eo hati + 2 Eo hatj where E0 = 100 N/C. The flux of this field through a circular surface of radius 0.02 m parallel to the Y-Z plane is nearly : (A) 0.125 Nm2/C (B) 0.02 Nm2/ C (C) 0.005 Nm2/ C (D) 3.14 Nm2/ C

Tardigrade Admin · Accepted Answer

φ =( E 0 hat i +2 E 0 hat j ) ⋅(π R 2) hat i φ =100 × π ×(0.02)2 =0.125

Q. The electric field in a region of space is given by, $E = E_{o} \hat{i} + 2 E_{o} \hat{j}$ where $E_{0} = 100 N / C$ . The flux of this field through a circular surface of radius $0.02 m$ parallel to the $Y - Z$ plane is nearly :

0.125 Nm²/C

0.02 Nm²/ C

0.005 Nm²/ C

3.14 Nm²/ C

$ϕ = (E_{0} \hat{i} + 2 E_{0} \hat{j}) \cdot (π R^{2}) \hat{i}$
$ϕ = 100 \times π \times (0.02)^{2}$
$= 0.125$

Q. The electric field in a region of space is given by, E=Eo​i^+2Eo​j^​ where E0​=100N/C. The flux of this field through a circular surface of radius 0.02m parallel to the Y−Z plane is nearly :

0.125 Nm2/C

0.02 Nm2/ C

0.005 Nm2/ C

3.14 Nm2/ C