The electric field in a region is radially outward and at a point is given by E=250 r V / m (where r is the distance of the point from origin). Calculate the charge contained in a sphere of radius 20 cm centred at the origin

Question

The electric field in a region is radially outward and at a point is given by E=250 r V / m (where r is the distance of the point from origin). Calculate the charge contained in a sphere of radius 20 cm centred at the origin (A) 2.22 × 10-6 C (B) 2.22 × 10-8 C (C) 2.22 × 10-10 C (D) Zero

Tardigrade Admin · Accepted Answer

E=(1/4 π ε0) ⋅ (Q/r2) 250 r=(9 × 109 ⋅ Q/r2) Use r=20 × 10-2 m Find Q=? Q=2.22 × 10-10 C

Q. The electric field in a region is radially outward and at a point is given by $E = 250 r V / m$ (where $r$ is the distance of the point from origin). Calculate the charge contained in a sphere of radius $20 c m$ centred at the origin

$2.22 \times 1 0^{- 6} C$

$2.22 \times 1 0^{- 8} C$

$2.22 \times 1 0^{- 10} C$

Zero

$E = \frac{1}{4 π ε _{0}} \cdot \frac{Q}{r ^{2}}$
$250 r = \frac{9 \times 1 0 ^{9} \cdot Q}{r ^{2}}$
Use $r = 20 \times 1 0^{- 2} m$
Find $Q = ?$
$Q = 2.22 \times 1 0^{- 10} C$

Q. The electric field in a region is radially outward and at a point is given by E=250rV/m (where r is the distance of the point from origin). Calculate the charge contained in a sphere of radius 20cm centred at the origin

2.22×10−6C

2.22×10−8C

2.22×10−10C