The electric field due to an infinitely long straight uniformly charged wire at a distance r is directly proportional to

Question

The electric field due to an infinitely long straight uniformly charged wire at a distance r is directly proportional to (A) r (B) r2 (C) (1/r) (D) (1/r2)

Tardigrade Admin · Accepted Answer

The electric field due to an infinitely long straight uniformly charged wire at a distance

r

is

E = \frac{λ}{2 π ε _{0} r}

where

λ

is the uniform linear charge density and

ε_{0}

is the permittivity of free space.

E \propto \frac{1}{r}

Q. The electric field due to an infinitely long straight uniformly charged wire at a distance $r$ is directly proportional to

$r$

$r^{2}$

$\frac{1}{r}$

$\frac{1}{r ^{2}}$

The electric field due to an infinitely long straight uniformly charged wire at a distance $r$ is
$E = \frac{λ}{2 π ε _{0} r}$
where $λ$ is the uniform linear charge density and
$ε_{0}$ is the permittivity of free space.
$E \propto \frac{1}{r}$

Q. The electric field due to an infinitely long straight uniformly charged wire at a distance r is directly proportional to

r

r2

r1​

r21​

The electric field due to an infinitely long straight uniformly charged wire at a distance r is E=2πε0​rλ​ where λ is the uniform linear charge density and ε0​ is the permittivity of free space. E∝r1​

Q. The electric field due to an infinitely long straight uniformly charged wire at a distance $r$ is directly proportional to

$r$

$r^{2}$

$\frac{1}{r}$

$\frac{1}{r ^{2}}$

The electric field due to an infinitely long straight uniformly charged wire at a distance $r$ is
$E = \frac{λ}{2 π ε _{0} r}$
where $λ$ is the uniform linear charge density and
$ε_{0}$ is the permittivity of free space.
$E \propto \frac{1}{r}$