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Tardigrade
Question
Chemistry
The effective atomic number of iron in [Fe(CN)6]3- is
Q. The effective atomic number of iron in
[
F
e
(
CN
)
6
]
3
−
is
4571
218
Coordination Compounds
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A
34
17%
B
36
32%
C
37
11%
D
35
40%
Solution:
O.S. of Fe in
[
F
e
(
CN
)
6
]
3
−
is +3
∴
E.A.N. = (26 - 3) + 6
×
2
= 2 3 + 12 = 35