Question

The effective atomic number of $Fe$ in $K_4\left[Fe(CN{)}_6\right]$ is

• A. 35
• B. 38
• C. 36
• D. 34

Answer 1

Answer: (C)

EAN $=$ Atomic No. $-$ Oxidation state $+2\times CN$
$=26-2+2\times 6$
$=36$