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  4. The effective atomic number of Fe in K 4[ Fe ( CN )6] is

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Q. The effective atomic number of $Fe$ in $K _{4}\left[ Fe ( CN )_{6}\right]$ is

Solution:

EAN $=$ Atomic No. $-$ Oxidation state $+2 \times CN$
$=26-2+2 \times 6$
$=36$