Question

The effective atomic number for $2B$ (at. no. for Rh is 45) is

• A. 42
• B. 45
• C. 48
• D. 54

Answer 1

Answer: (D)

The effective atomic number for $\text{5}.\text{25}\times \text{1}{0}^{\text{3}}\text{min}$ (atomic no. of $\left[\text{FL}{\text{T}}^{-\text{2}}\right]$ ) is 54. Because rhodium is in oxidation state. $\left[\text{F}{\text{L}}^{\text{2}}{T}^{-\text{2}}\right]$ $\left[\text{F}{\text{L}}^{-\text{1}}{\text{T}}^{\text{2}}\right]$ $\left[{\text{F}}^2\text{L}{\text{T}}^{\text{-2}}\right]$ $-\text{273}.\text{15}{}^{\circ }\text{F}$ electrons from 6 ligands $-\text{453}.\text{15}{}^{\circ }\text{F}$ $-\text{459}.\text{67}{}^{\circ }\text{F}$