The effect of addition of helium gas to the following reaction in equilibrium state, is: PCl ( g ) leftharpoons PCl 3( g )+ Cl 2( g )

Question

The effect of addition of helium gas to the following reaction in equilibrium state, is: PCl ( g ) leftharpoons PCl 3( g )+ Cl 2( g ) (A) addition of helium will not affect the equilibrium. (B) the equilibrium will shift in the forward direction and more of Cl 2 and PCl 3 gases will be produced. (C) the equilibrium will go backward due to suppression of dissociation of PCl 5. (D) helium will deactivate PCl 5 and reaction will stop.

Tardigrade Admin · Accepted Answer

PCl ( g ) leftharpoons PCl 3( g )+ Cl 2( g ) (Case 1: At constant P - volume will increase so reaction will shift in forward direction then answer will be A Case 2: At constant volume no change in active mass so reaction will not shift in any direction then answer will be D.

Q. The effect of addition of helium gas to the following reaction in equilibrium state, is : $PCl (g) ⇌ PC l_{3} (g) + C l_{2} (g)$

addition of helium will not affect the equilibrium.

the equilibrium will shift in the forward direction and more of $C l_{2}$ and $PC l_{3}$ gases will be produced.

the equilibrium will go backward due to suppression of dissociation of $PC l_{5}$ .

helium will deactivate $PC l_{5}$ and reaction will stop.

$PCl (g) ⇌ PC l_{3} (g) + C l_{2} (g)$
(Case 1 : At constant $P$ - volume will increase so reaction will shift in forward direction then answer will be $A$
Case 2 : At constant volume no change in active mass so reaction will not shift in any direction then answer will be D.

Q. The effect of addition of helium gas to the following reaction in equilibrium state, is : PCl(g)⇌PCl3​(g)+Cl2​(g)

addition of helium will not affect the equilibrium.

the equilibrium will shift in the forward direction and more of Cl2​ and PCl3​ gases will be produced.

the equilibrium will go backward due to suppression of dissociation of PCl5​.

helium will deactivate PCl5​ and reaction will stop.

PCl(g)⇌PCl3​(g)+Cl2​(g) (Case 1 : At constant P - volume will increase so reaction will shift in forward direction then answer will be A Case 2 : At constant volume no change in active mass so reaction will not shift in any direction then answer will be D.

Q. The effect of addition of helium gas to the following reaction in equilibrium state, is : $PCl (g) ⇌ PC l_{3} (g) + C l_{2} (g)$

the equilibrium will shift in the forward direction and more of $C l_{2}$ and $PC l_{3}$ gases will be produced.

the equilibrium will go backward due to suppression of dissociation of $PC l_{5}$ .

helium will deactivate $PC l_{5}$ and reaction will stop.

$PCl (g) ⇌ PC l_{3} (g) + C l_{2} (g)$
(Case 1 : At constant $P$ - volume will increase so reaction will shift in forward direction then answer will be $A$
Case 2 : At constant volume no change in active mass so reaction will not shift in any direction then answer will be D.