The ease of hydrolysis in the compounds CH 3 COCl ( I ), CH 3- CO - O - COCH 3( II ) CH 3 COOC 2 H 5( III ) and CH 3 CONH 2( IV ) is of the order

Question

The ease of hydrolysis in the compounds CH 3 COCl ( I ), CH 3- CO - O - COCH 3( II ) CH 3 COOC 2 H 5( III ) and CH 3 CONH 2( IV ) is of the order (A) I > II > III > IV (B) IV > III > II > I (C) I > II > IV > III (D) II > I > IV > III

Tardigrade Admin · Accepted Answer

The ease of hydrolysis of carbonyl compounds depend on the group attached to the carbonyl carbon. Among the given options, chlorine

(- Cl)

group is electron withdrawing group which makes the carbonyl group electrophilic. Hence, hydrolysis can occur most easily. The order for electron withdrawing tendency among given options is as follows:

- Cl > - OCOC H_{3} > - O C_{2} H_{5} > - N H_{2}

So, the correct order for the ease of hydrolysis in the given compounds is as follows:

I C H_{3} COCl > II C H_{3} COOCOC H_{3} > III C H_{3} COO C_{2} H_{5} > I V C H_{3} CON H_{2}

Q. The ease of hydrolysis in the compounds CH3​COCl(I),CH3​−CO−O−COCH3​(II) CH3​COOC2​H5​(III) and CH3​CONH2​(IV) is of the order

I > II > III > IV

IV > III > II > I

I > II > IV > III

II > I > IV > III

Q. The ease of hydrolysis in the compounds $C H_{3} COCl (I), C H_{3} - CO - O - COC H_{3} (II)$ $C H_{3} COO C_{2} H_{5} (III)$ and $C H_{3} CON H_{2} (I V)$ is of the order