The earth (mass = 6× 1024 kg ) revolves around the sun with angular velocity 2× 10- 7 rad s- 1 in a circular orbit of radius 1.5× 1011 m . The force exerted by the sun on the earth (in newton) is

Question

The earth (mass = 6× 1024 kg ) revolves around the sun with angular velocity 2× 10- 7 rad s- 1 in a circular orbit of radius 1.5× 1011 m . The force exerted by the sun on the earth (in newton) is (A) zero (B) 18× 1025 (C) 27× 1039 (D) 36× 1021

Tardigrade Admin · Accepted Answer

Gravitational force exerted by the sun on the earth will provide the required centripetal force. F=mRω 2 =6× (10)24× (1.5 × (10)11)(2 × (10)- 7)2 =36× 1021 N

Q. The earth (mass = $6 \times 1 0^{24} k g$ ) revolves around the sun with angular velocity $2 \times 1 0^{- 7} r a d s^{- 1}$ in a circular orbit of radius $1.5 \times 1 0^{11} m$ . The force exerted by the sun on the earth (in newton) is

$zero$

$18 \times 1 0^{25}$

$27 \times 1 0^{39}$

$36 \times 1 0^{21}$

Gravitational force exerted by the sun on the earth will provide the required centripetal force.
$F = m R ω^{2}$
$= 6 \times (10)^{24} \times (1.5 \times (10)^{11}) (2 \times (10)^{- 7})^{2}$
$= 36 \times 1 0^{21} N$

Q. The earth (mass = 6×1024kg ) revolves around the sun with angular velocity 2×10−7rads−1 in a circular orbit of radius 1.5×1011m . The force exerted by the sun on the earth (in newton) is

zero

18×1025

27×1039

36×1021