The E° for half cells Fe/Fe2+ and Cu/Cu2+ are -0.44 text V and +0.32 text V respectively. Then:

Question

The E° for half cells Fe/Fe2+ and Cu/Cu2+ are -0.44 text V and +0.32 text V respectively. Then: (A)  Cu2+ oxidises Fe  (B)  Cu2+ oxidises Fe2+  (C)  Cu oxidises Fe2+  (D)  Cu reduces Fe2+

Tardigrade Admin · Accepted Answer

The standard reduction potential of Fe2+/Fe, is less than that of Cu2+/Cu, hence Fe is more electropositive than copper. Hence, Cu2+ can oxidise Fe .

Q. The $E^{\circ}$ for half cells $F e / F e^{2 +}$ and $C u / C u^{2 +}$ are $- 0.44 V$ and $+ 0.32 V$ respectively. Then:

$C u^{2 +}$ oxidises $F e$

$C u^{2 +}$ oxidises $F e^{2 +}$

$C u$ oxidises $F e^{2 +}$

$C u$ reduces $F e^{2 +}$

The standard reduction potential of $F e^{2 +} / F e,$ is less than that of $C u^{2 +} / C u,$ hence Fe is more electropositive than copper. Hence, $C u^{2 +}$ can oxidise $F e$ .

Q. The E∘ for half cells Fe/Fe2+ and Cu/Cu2+ are −0.44V and +0.32V respectively. Then:

Cu2+ oxidises Fe

Cu2+ oxidises Fe2+

Cu oxidises Fe2+

Cu reduces Fe2+