The drift velocity of the electrons in a copper wire of length 2 m under the application of a potential difference of 220 V is 0.5 text ms-1 . Their mobility (in m2V-1s-1 )

Question

The drift velocity of the electrons in a copper wire of length 2 m under the application of a potential difference of 220 V is 0.5 text ms-1 . Their mobility (in m2V-1s-1 ) (A)  2.5× 10-3  (B)  2.5× 10-2  (C)  5× 102  (D)  5× 10-3

Tardigrade Admin · Accepted Answer

Drift velocity = mobility x intensity of electric field or vd=μ E or μ =(vd/E) or μ =(vd/V/l) ( ∵ E=(V/l) ) ∴ μ =(0.5× 2/220)=4.5× 10-3 ≈ 5× 10-3m2V-1s-1

Q. The drift velocity of the electrons in a copper wire of length $2 m$ under the application of a potential difference of $220 V$ is $0.5 m s^{- 1}$ . Their mobility (in $m^{2} V^{- 1} s^{- 1}$ )

$2.5 \times 10^{- 3}$

$2.5 \times 10^{- 2}$

$5 \times 10^{2}$

$5 \times 10^{- 3}$

$5 \times 10^{- 2}$

Drift velocity = mobility x intensity of electric field or
$v_{d} = μ E$ or $μ = \frac{v _{d}}{E}$
or $μ = \frac{v _{d}}{V / l}$
$(∵ E = \frac{V}{l})$
$∴$ $μ = \frac{0.5 \times 2}{220} = 4.5 \times 10^{- 3}$
$\approx 5 \times 10^{- 3} m^{2} V^{- 1} s^{- 1}$

Q. The drift velocity of the electrons in a copper wire of length 2m under the application of a potential difference of 220V is 0.5ms−1 . Their mobility (in m2V−1s−1 )

2.5×10−3

2.5×10−2

5×102

5×10−3

5×10−2

Drift velocity = mobility x intensity of electric field or vd​=μE or μ=Evd​​ or μ=V/lvd​​ (∵E=lV​) ∴ μ=2200.5×2​=4.5×10−3 ≈5×10−3m2V−1s−1