The drift velocity of electrons in silver wire with cross sectional area 3.14 × 10-6 m 2 carrying a current of 20 A is. Given atomic weight of A g=108, density of silver = 10.5 × 103 kg / m 3.

Question

The drift velocity of electrons in silver wire with cross sectional area 3.14 × 10-6 m 2 carrying a current of 20 A is. Given atomic weight of A g=108, density of silver = 10.5 × 103 kg / m 3. (A) 2.798 × 10-54 m/ sec  (B) 67.98 × 10-54 m/ sec  (C) 0.67 × 10-54 m/ sec  (D) 6.798 × 10-54 m/ sec

Tardigrade Admin · Accepted Answer

Number of electrons per kg of silver (6.023 × 1026/108) Number of electrons per unit volume of silver n=(6.023 × 1026/108) × 10.5 × 103 vd=(I/n e A) =(20/6.023 × 1026 × 10.5 × 103 × 1.6 × 10-19 × 3.14 × 10-6) × 108 =6.798 × 10-4 m /sec .

Q. The drift velocity of electrons in silver wire with cross sectional area $3.14 \times 1 0^{- 6} m^{2}$ carrying a current of $20 A$ is. Given atomic weight of $A g = 108$ , density of silver = $10.5 \times 1 0^{3} k g / m^{3}$ .

$2.798 \times 1 0^{- 54} m / sec$

$67.98 \times 1 0^{- 54} m / sec$

$0.67 \times 1 0^{- 54} m / sec$

$6.798 \times 1 0^{- 54} m / sec$

Q. The drift velocity of electrons in silver wire with cross sectional area 3.14×10−6m2 carrying a current of 20A is. Given atomic weight of Ag=108, density of silver = 10.5×103kg/m3.

2.798×10−54m/sec

67.98×10−54m/sec

0.67×10−54m/sec

6.798×10−54m/sec

Number of electrons per kg of silver 1086.023×1026​ Number of electrons per unit volume of silver n=1086.023×1026​×10.5×103 vd​=neAI​ =6.023×1026×10.5×103×1.6×10−19×3.14×10−620​ ×108 =6.798×10−4m/sec.

Q. The drift velocity of electrons in silver wire with cross sectional area $3.14 \times 1 0^{- 6} m^{2}$ carrying a current of $20 A$ is. Given atomic weight of $A g = 108$ , density of silver = $10.5 \times 1 0^{3} k g / m^{3}$ .

$2.798 \times 1 0^{- 54} m / sec$

$67.98 \times 1 0^{- 54} m / sec$

$0.67 \times 1 0^{- 54} m / sec$

$6.798 \times 1 0^{- 54} m / sec$