Function cos−1(log2(x2+5x+8))
The function should exist when −1≤log2(x2+5x+8)≤1
We take only, log2(x2+5x+8)≤1 ⇒x2+5x+8≤(2)1 {∵−1≤log2(x2+5x+8)
given imaginary values } ⇒x2+5x+6≤0 ⇒(x+2)(x+3)≤0 ⇒x∈[−3,−2]
Hence, the domain of the function is −3≤x≤−2