Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
The distance travelled by an object along a straight line in time t is given by s=3-4t+5t2, the initial velocity of the object is
Q. The distance travelled by an object along a straight line in time
t
is given by
s
=
3
−
4
t
+
5
t
2
,
the initial velocity of the object is
2738
224
WBJEE
WBJEE 2008
Motion in a Straight Line
Report Error
A
3 unit
20%
B
-3 unit
11%
C
4 unit
23%
D
- 4 unit
46%
Solution:
Given distance travelled by an object along a straight line in time
t
is
3
−
4
t
+
5
t
2
Here, the velocity
d
t
d
s
=
−
4
+
10
t
Hence, initial velocity will be
∣
∣
u
=
d
t
d
s
∣
∣
t
=
0
=
−
4
unit