Q.
The distance of the point P(4,6,−2) from the line passing through the point (−3,2,3) and parallel to a line with direction ratios 3,3,−1 is equal to :
Equation of line is 3x+3=3y−2=−1z−3=λ M(3λ−3,3λ+2,3−λ)
D.R of PM( 3λ−7,3λ−4,5−λ)
Since PM is perpendicular to line ⇒3(3λ−7)+3(3λ−4)−1(5−λ)=0 ⇒λ=2 ⇒M(3,8,1)⇒PM=14