Question

The distance of the point $(7,-3,-4)$ from the plane passing through the points $(2,-3,1),(-1,1,-2)$ and $(3,-4,2)$ is :

• A. $5\sqrt{2}$
• B. $4\sqrt{2}$
• C. 4
• D. 5

Answer 1

Answer: (D)

$=\left|\begin{array}{ccc}x-2& y+3& z-1\\ -3& 4& -3\\ 4& -5& 4\end{array}\right|=0$
$x-z-1=0$
Distance of $P(7,-3,-4)$ from Plane is
$d=\left|\frac{7+4-1}{\sqrt{2}}\right|=5\sqrt{2}$