Question

The distance of the point (3, 4, 5) from X-axis is

• A. 3
• B. 5
• C. $\sqrt{34}$
• D. $\sqrt{41}$

Answer 1

Answer: (D)

The foot of perpendicular from (3, 4, 5) on X-axis is (3, 0, 0). Hence, the required distance
$=\sqrt{(3-3{)}^2+(4-0{)}^2+(5-0{)}^2}=\sqrt{41}$.