The distance of the plane vecr ⋅ (3 hati + 4 hatj + 12 hatk ) = 65 from the origin is

Question

The distance of the plane vecr ⋅ (3 hati + 4 hatj + 12 hatk ) = 65 from the origin is (A) 65 (B) 5 (C) -5 (D) none of these

Tardigrade Admin · Accepted Answer

The given equation is vecr . (3 hati + 4 hatj + 12 hatk) = 65 or vecr . ( (3/13) hati + (4/13) hatj + (12/13) hatk ) = 5 , which is of the form vecr . hatn = p

Q. The distance of the plane $r \cdot (3 \hat{i} + 4 \hat{j} + 12 \hat{k}) = 65$ from the origin is

65

5

-5

none of these

The given equation is $r . (3 \hat{i} + 4 \hat{j} + 12 \hat{k}) = 65$
or $r . (\frac{3}{13} \hat{i} + \frac{4}{13} \hat{j} + \frac{12}{13} \hat{k}) = 5$ ,
which is of the form $r . \overset{n}{^} = p$

Q. The distance of the plane r⋅(3i^+4j^​+12k^)=65 from the origin is

65

5

-5

none of these

The given equation is r.(3i^+4j^​+12k^)=65 or r.(133​i^+134​j^​+1312​k^)=5 , which is of the form r.n^=p

Q. The distance of the plane $r \cdot (3 \hat{i} + 4 \hat{j} + 12 \hat{k}) = 65$ from the origin is

The given equation is $r . (3 \hat{i} + 4 \hat{j} + 12 \hat{k}) = 65$
or $r . (\frac{3}{13} \hat{i} + \frac{4}{13} \hat{j} + \frac{12}{13} \hat{k}) = 5$ ,
which is of the form $r . \overset{n}{^} = p$