The distance of centre of mass of a uniform semicircular disc of radius R , from the geometric center on the axis of symmetry is

Question

The distance of centre of mass of a uniform semicircular disc of radius R , from the geometric center on the axis of symmetry is (A) (4 R/3 π ) (B) (2 R/3 π ) (C) (4 R/9 π ) (D) (2 R/π )

Tardigrade Admin · Accepted Answer

Centre of mass of a uniform semicircular disc of radius R lies at a distance of h = (4 textR/3 π ) from the centre on the axis of symmetry as shown in figure. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-jiiyk7pdwbs2.png" />

Q. The distance of centre of mass of a uniform semicircular disc of radius $R$ , from the geometric center on the axis of symmetry is

$\frac{4 R}{3 π}$

$\frac{2 R}{3 π}$

$\frac{4 R}{9 π}$

$\frac{2 R}{π}$

Centre of mass of a uniform semicircular disc of radius $R$ lies at a distance of $h = \frac{4 R}{3 π}$ from the centre on the axis of symmetry as shown in figure.

Q. The distance of centre of mass of a uniform semicircular disc of radius R , from the geometric center on the axis of symmetry is

3π4R​

3π2R​

9π4R​

π2R​