The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 overset texto mathop textA . Given, mass of carbon atom is 12 amu and mass of oxygen atom is 16 amu. Calculate the position of the centre of mass of the carbon monoxide molecule:

Question

The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 overset texto mathop textA . Given, mass of carbon atom is 12 amu and mass of oxygen atom is 16 amu. Calculate the position of the centre of mass of the carbon monoxide molecule: (A)  6.3 overset texto mathop textA from the carbon atom (B)  1 overset texto mathop textA from the oxygen atom (C)  0.63 overset texto mathop textA from the carbon atom (D)  0.12 overset texto mathop textA from the oxygen atom

Tardigrade Admin · Accepted Answer

Let xcm be distance of centre of mass from C-atom xcm=(m1x1+m2x2/m1+m2)=(12× 0+16× 1.1/12+16) =0.63 overset texto mathop textA

Q. The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is $1.1 A o$ . Given, mass of carbon atom is 12 amu and mass of oxygen atom is 16 amu. Calculate the position of the centre of mass of the carbon monoxide molecule:

$6.3 A o$ from the carbon atom

$1 A o$ from the oxygen atom

$0.63 A o$ from the carbon atom

$0.12 A o$ from the oxygen atom

$0.16 A o$ from the carbon atom

Let $x_{c m}$ be distance of centre of mass from C-atom
$x_{c m} = \frac{m _{1} x _{1} + m _{2} x _{2}}{m _{1} + m _{2}} = \frac{12 \times 0 + 16 \times 1.1}{12 + 16}$
$= 0.63 A o$

Q. The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1Ao . Given, mass of carbon atom is 12 amu and mass of oxygen atom is 16 amu. Calculate the position of the centre of mass of the carbon monoxide molecule:

6.3Ao from the carbon atom

1Ao from the oxygen atom

0.63Ao from the carbon atom

0.12Ao from the oxygen atom

0.16Ao from the carbon atom

Let xcm​ be distance of centre of mass from C-atom xcm​=m1​+m2​m1​x1​+m2​x2​​=12+1612×0+16×1.1​ =0.63Ao