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Tardigrade
Question
Chemistry
The distance between Na+ and Cl- ions in NaCl with a density 3.165 g cm-3 is
Q. The distance between
N
a
+
and
C
l
−
ions in
N
a
Cl
with a density
3.165
g
c
m
−
3
is
1843
192
The Solid State
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A
497
p
m
6%
B
248.5
p
m
73%
C
234
p
m
15%
D
538.5
p
m
6%
Solution:
d
=
a
3
×
N
A
Z
×
M
a
3
=
d
×
N
A
Z
×
M
=
3.165
×
6.023
×
1
0
23
4
×
58.5
a
3
=
122.77
×
1
0
−
24
c
m
3
a
=
4.97
×
1
0
−
8
c
m
or
497
p
m
Distance between
N
a
+
and
C
l
−
=
2
a
=
2
497
=
248.5
p
m