The distance between H + and Cl- ions in HCl molecule is 1.28 mathringA. What will be the potential due to this dipole at a distance of 12 mathringA from one end and on the axis of dipole?

Question

The distance between H + and Cl- ions in HCl molecule is 1.28 mathringA. What will be the potential due to this dipole at a distance of 12 mathringA from one end and on the axis of dipole? (A) 0.13 V (B) 1.3 V (C) 13 V (D) 130 V

Tardigrade Admin · Accepted Answer

V =9 × 109 ⋅ (p/r2) =9 × 109 × ((1.6 × 10-19) × 1.28 × 10-10/(12 × 10-10)2) =0.13 V

Q. The distance between $H^{+}$ and $C l^{-}$ ions in $H Cl$ molecule is $1.28 \overset{˚}{A}$ . What will be the potential due to this dipole at a distance of $12 \overset{˚}{A}$ from one end and on the axis of dipole?

0.13 V

1.3 V

13 V

130 V

$V = 9 \times 1 0^{9} \cdot \frac{p}{r ^{2}}$
$= 9 \times 1 0^{9} \times \frac{( 1.6 \times 1 0 ^{- 19} ) \times 1.28 \times 1 0 ^{- 10}}{( 12 \times 1 0 ^{- 10} ) ^{2}}$
$= 0.13 V$

Q. The distance between H+ and Cl− ions in HCl molecule is 1.28A˚. What will be the potential due to this dipole at a distance of 12A˚ from one end and on the axis of dipole?