The distance between a proton and electron both having a charge 1.6 × 10-19 C of a hydrogen atom is 10-12 metre. The value of intensity of electric field produced on electron due to proton will be

Question

The distance between a proton and electron both having a charge 1.6 × 10-19 C of a hydrogen atom is 10-12 metre. The value of intensity of electric field produced on electron due to proton will be (A) 14.4 × 1014 N / C (B) 12.2 × 1014 N / C (C) 11.4 × 1014 N / C (D) 13.2 × 1014 N / C

Tardigrade Admin · Accepted Answer

E =( Kq / r 2)=(9 × 109 × 1.6 × 10-19/(10-12)2) E =9 × 109 × 1.6 × 10-19 × 1024 =14.4 × 1014 N / C

Q. The distance between a proton and electron both having a charge $1.6 \times 1 0^{- 19} C$ of a hydrogen atom is $1 0^{- 12}$ metre. The value of intensity of electric field produced on electron due to proton will be

$14.4 \times 1 0^{14} N / C$

$12.2 \times 1 0^{14} N / C$

$11.4 \times 1 0^{14} N / C$

$13.2 \times 1 0^{14} N / C$

$E = \frac{K q}{r ^{2}} = \frac{9 \times 1 0 ^{9} \times 1.6 \times 1 0 ^{- 19}}{( 1 0 ^{- 12} ) ^{2}}$
$E = 9 \times 1 0^{9} \times 1.6 \times 1 0^{- 19} \times 1 0^{24}$
$= 14.4 \times 1 0^{14} N / C$

Q. The distance between a proton and electron both having a charge 1.6×10−19C of a hydrogen atom is 10−12 metre. The value of intensity of electric field produced on electron due to proton will be

14.4×1014N/C

12.2×1014N/C

11.4×1014N/C

13.2×1014N/C