Question

The distance between $3rd$ and $2nd$ orbit of hydrogen atom is :

• A. $2.646\times 10^{-8}cm$
• B. $2.116\times 10^{-8}cm$
• C. $1.058\times 10^{-8}cm$
• D. $0.529\times 10^{-8}cm$

Answer 1

Answer: (A)

$r_3-r_2=\frac{0.529}{1}(9-4)\stackrel{{}^{\circ }}{A}$
$=0.529\times 5\times 10^{-8}cm$
$=2.646\times 10^{-8}cm$