The dissociation constants of two acids HA1 and HA2 are 3.0 × 10-4 and 1.8 × 10-5 respectively.The relative strengths of the acids will be

Question

The dissociation constants of two acids HA1 and HA2 are 3.0 × 10-4 and 1.8 × 10-5 respectively.The relative strengths of the acids will be (A) 1: 4 (B) 4: 1 (C) 1: 16 (D) 16: 1

Tardigrade Admin · Accepted Answer

( textStrength of acid HA1/ textStrength of acid HA2)=√(K1/K2) =√(3.0×10-4/1.8×10-5)=(4/1)

Q. The dissociation constants of two acids $H A_{1}$ and $H A_{2}$ are $3.0 \times 1 0^{- 4}$ and $1.8 \times 1 0^{- 5}$ respectively.The relative strengths of the acids will be

1 : 4

4 : 1

1 : 16

16 : 1

$\frac{Strength of acid H A _{1}}{Strength of acid H A _{2}} = \frac{K _{1}}{K _{2}}$
$= \frac{3.0 \times 1 0 ^{- 4}}{1.8 \times 1 0 ^{- 5}} = \frac{4}{1}$

Q. The dissociation constants of two acids HA1​ and HA2​ are 3.0×10−4 and 1.8×10−5 respectively.The relative strengths of the acids will be