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Q.
The dissociation constants of two acids $HA_1$ and $HA_2$ are $3.0\, \times \, 10^{-4}$ and $1.8\, \times \,10^{-5}$ respectively.The relative strengths of the acids will be
Equilibrium
Solution:
$\frac{\text{Strength of acid} HA_{1}}{\text{Strength of acid} HA_{2}}=\sqrt{\frac{K_{1}}{K_{2}}}$
$=\sqrt{\frac{3.0\times10^{-4}}{1.8\times10^{-5}}}=\frac{4}{1}$