The disproportionation of MnO 42- in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, then the spin-only magnetic moment (μ) value of B in B M is

Question

The disproportionation of MnO 42- in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, then the spin-only magnetic moment (μ) value of B in B M is  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

MnO 42- stackrel H + longrightarrow MnO 4-+ MnO 2 No. of unpaired overline e =3 ∴ μ=√15=3.877 Nearest Integer =4

Q. The disproportionation of $M n O_{4}^{2 -}$ in acidic medium resulted in the formation of two manganese compounds $A$ and $B$ . If the oxidation state of $M n$ in $B$ is smaller than that of A, then the spin-only magnetic moment $(μ)$ value of $B$ in $BM$ is ___

$M n O_{4}^{2 -} ⟶ H^{+} M n O_{4}^{-} + M n O_{2}$
No. of unpaired $\overline{e} = 3$
$∴ μ = 15 = 3.877$
Nearest Integer $= 4$

Q. The disproportionation of MnO42−​ in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, then the spin-only magnetic moment (μ) value of B in BM is ___

MnO42−​⟶H+​MnO4−​+MnO2​ No. of unpaired e=3 ∴μ=15​=3.877 Nearest Integer =4

Q. The disproportionation of $M n O_{4}^{2 -}$ in acidic medium resulted in the formation of two manganese compounds $A$ and $B$ . If the oxidation state of $M n$ in $B$ is smaller than that of A, then the spin-only magnetic moment $(μ)$ value of $B$ in $BM$ is ___

$M n O_{4}^{2 -} ⟶ H^{+} M n O_{4}^{-} + M n O_{2}$
No. of unpaired $\overline{e} = 3$
$∴ μ = 15 = 3.877$
Nearest Integer $= 4$