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Tardigrade
Question
Physics
The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t=√x+3, where x is in meters and t is in seconds. The work done by the force in the first 6 seconds is
Q. The displacement
x
of a particle moving in one dimension under the action of a constant force is related to the time
t
by the equation
t
=
x
+
3
,
where x is in meters and
t
is in seconds. The work done by the force in the first
6
seconds is
2479
181
Work, Energy and Power
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A
9 J
44%
B
6 J
11%
C
0 J
22%
D
3 J
22%
Solution:
x
=
(
t
−
3
)
2
⇒
v
=
d
t
d
x
=
2
(
t
−
3
)
at
t
=
0
;
v
1
=
−
6
m
/
s
and at
t
=
6
sec
,
v
2
=
6
m
/
s
so, change in kinetic energy
=
W
=
2
1
m
v
2
2
−
2
1
m
v
1
2
=
0