The displacement x of a particle at the instant when its velocity v is given by v = √3x+16. Its acceleration and initial velocity are

Question

The displacement x of a particle at the instant when its velocity v is given by v = √3x+16. Its acceleration and initial velocity are (A) 1.5 units, 4 units (B) 3 units, 4 units (C) 16 units, 1.6 units (D) 16 units, 3 units

Tardigrade Admin · Accepted Answer

Given: v = √3x + 16 Squaring both sides, we get v2 = 3x + 16 or v2 - 16 = 3x Comparing with v2 -u2 = 2aS, we get, u = 4 units 2a = 3 or a = 15 units

Q. The displacement x of a particle at the instant when its velocity v is given by $v = 3 x + 16$ . Its acceleration and initial velocity are

1.5 units, 4 units

3 units, 4 units

16 units, 1.6 units

16 units, 3 units

Given : $v = 3 x + 16$
Squaring both sides, we get
$v^{2} = 3 x + 16$ or $v^{2} - 16 = 3 x$
Comparing with $v^{2} - u^{2} = 2 a S,$ we get,
$u = 4$ units
$2 a = 3$ or $a = 15$ units

Q. The displacement x of a particle at the instant when its velocity v is given by v=3x+16​. Its acceleration and initial velocity are