Question

The displacement (x) of a particle as a function of time (t) is given by; $x=a\sin (bt+c)$ where a, b and c are constants of motion. Choose the correct statements from the following.

• A. The motion repeats itself in a time interval of $\frac{2\pi }{b}$
• B. The energy of the particle remains constant
• C. The velocity of the particle is zero at x =$\pm$a
• D. all of the above

Answer 1

Answer: (A), (B), (C)

The motion of the particle is simple harmonic.
The displacement at time $t$ is $x=a\sin (bt+c)$
Therefore,displacement at time $(t+(2\pi /b))$ is
$x$ at $\left(t+\frac{2\pi }{b}\right)=a\sin \left[b\left(t+\frac{2\pi }{b}\right)+c\right]$
$=a\sin [bt+c+2\pi ]=a\sin (bt+c)=x($ at time $t)$
Hence, statement (a) is correct.
Statement (b) is also correct since the same displacement is recovered after a time interval of $(2\pi /b)$.
Statement (c) is correct because the velocity is zero when the displacement $=\pm$ the amplitude, i.e at the extreme ends of the motion.
Statement (d) is incorrect, the acceleration is maximum (in magnitude ) at $x=\pm A.$