Question

The displacement-time graph for two particles $A$ and $B$ is as follows. The ratio $\frac{V_A}{V_B}$ is

• A. $1:2$
• B. $1:\sqrt{3}$
• C. $\sqrt{3}:1$
• D. $1:3$

Answer 1

Answer: (D)

The slope of line $A$ is $\tan 30^{\circ }$ and $B=\tan 60^{\circ }$
$\frac{v_A}{v_B}=\frac{\tan 30^{\circ }}{\tan 60^{\circ }}=\frac{\frac{1}{\sqrt{3}}}{\sqrt{3}}=\frac{1}{3}$
$\Rightarrow v_A:v_B=1:3$