The displacement of a particle, starting from rest (at t = 0) is given by s = 6t2 -t3 The time in seconds at which the particle will obtain zero velocity again is

Question

The displacement of a particle, starting from rest (at t = 0) is given by s = 6t2 -t3 The time in seconds at which the particle will obtain zero velocity again is (A) 2 (B) 4 (C) 6 (D) 8

Tardigrade Admin · Accepted Answer

Given s = 6t2 - t3 Velocity v = (ds/dt)=12 t-3t2 If velocity is zero, then 0 = 12t - 3t2 ⇒ t=4 s

Q. The displacement of a particle, starting from rest (at t = 0) is given by $s = 6 t^{2} - t^{3}$ The time in seconds at which the particle will obtain zero velocity again is

2

4

6

8

Given s = 6 $t^{2} - t^{3}$
Velocity v = $\frac{d s}{d t} = 12 t - 3 t^{2}$
If velocity is zero, then 0 = $12 t - 3 t^{2}$
$\Rightarrow$ t=4 s

Q. The displacement of a particle, starting from rest (at t = 0) is given by s=6t2−t3 The time in seconds at which the particle will obtain zero velocity again is

2

4

6

8

Given s = 6t2−t3 Velocity v = dtds​=12t−3t2 If velocity is zero, then 0 = 12t−3t2 ⇒ t=4 s

Q. The displacement of a particle, starting from rest (at t = 0) is given by $s = 6 t^{2} - t^{3}$ The time in seconds at which the particle will obtain zero velocity again is

Given s = 6 $t^{2} - t^{3}$
Velocity v = $\frac{d s}{d t} = 12 t - 3 t^{2}$
If velocity is zero, then 0 = $12 t - 3 t^{2}$
$\Rightarrow$ t=4 s