The displacement of a particle in SHM is x=10 sin (2t-(π/6)) metre. When its displacement is 6 m, the velocity of the particle (in ms-1) is

Question

The displacement of a particle in SHM is x=10 sin (2t-(π/6)) metre. When its displacement is 6 m, the velocity of the particle (in ms-1) is (A) 8 (B) 24 (C) 10 (D) 12

Tardigrade Admin · Accepted Answer

Given, x=10 sin (2 t-(π/6)) x=6 m Here, ω=2 and A=10 We know that for SHM, v=ω √A2-x2 v=2 √102-62 v=2 × 8 v=16 ms -1

Q. The displacement of a particle in SHM is $x = 10 s in (2 t - \frac{π}{6})$ metre. When its displacement is $6 m$ , the velocity of the particle (in $m s^{- 1}$ ) is

$8$

$24$

10

$12$

16

Given, $x = 10 sin (2 t - \frac{π}{6})$
$x = 6 m$
Here, $ω = 2$ and $A = 10$
We know that for SHM,
$v = ω A^{2} - x^{2}$
$v = 2 1 0^{2} - 6^{2}$
$v = 2 \times 8$
$v = 16 m s^{- 1}$

Q. The displacement of a particle in SHM is x=10sin(2t−6π​) metre. When its displacement is 6m, the velocity of the particle (in ms−1) is

8

24

10

12

16

Given, x=10sin(2t−6π​) x=6m Here, ω=2 and A=10 We know that for SHM, v=ωA2−x2​ v=2102−62​ v=2×8 v=16ms−1

Q. The displacement of a particle in SHM is $x = 10 s in (2 t - \frac{π}{6})$ metre. When its displacement is $6 m$ , the velocity of the particle (in $m s^{- 1}$ ) is

$8$

$24$

$12$

Given, $x = 10 sin (2 t - \frac{π}{6})$
$x = 6 m$
Here, $ω = 2$ and $A = 10$
We know that for SHM,
$v = ω A^{2} - x^{2}$
$v = 2 1 0^{2} - 6^{2}$
$v = 2 \times 8$
$v = 16 m s^{- 1}$