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Tardigrade
Question
Physics
The displacement of a particle from its mean position (in m ) is given by, y=0.2sin (10 π t + 1.5 π ) cos (.10π t+1.5π ). The motion of particle is
Q. The displacement of a particle from its mean position (in
m
) is given by,
y
=
0.2
s
in
(
10
π
t
+
1.5
π
)
cos
(
10
π
t
+
1.5
π
)
.
The motion of particle is
117
157
NTA Abhyas
NTA Abhyas 2022
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A
periodic but not S.H.M
B
non-periodic
C
simple harmonic motion with a period
0.1
s
D
simple harmonic motion with a period
0.2
s
Solution:
y
=
0.2
s
in
(
10
π
t
+
1.5
π
)
cos
(
10
π
t
+
1.5
π
)
=
0.1
s
in
2
(
10
π
t
+
1.5
π
)
[
∵
s
in
2
A
=
2
s
in
A
cos
A
]
=
0.1
s
in
(
20
π
t
+
3.0
π
)
∴
Time period
T
=
ω
2
π
=
20
π
2
π
=
10
1
=
0.1
s