The direction ratios of the line which is perpendicular to the lines (x-7/2) = (y+17/-3) = (z-6/1) and (x+5/1) = (y+3/2) = (z-4/-2) are

Question

The direction ratios of the line which is perpendicular to the lines (x-7/2) = (y+17/-3) = (z-6/1) and (x+5/1) = (y+3/2) = (z-4/-2) are (A) < 4, 5 , 7 > (B) < 4, - 5 , 7 > (C) < 4, - 5, - 7 > (D) < - 4, 5 , 7 >

Tardigrade Admin · Accepted Answer

Correct answer is (a) < 4, 5 , 7 >

Q. The direction ratios of the line which is perpendicular to the lines 2x−7​=−3y+17​=1z−6​ and 1x+5​=2y+3​=−2z−4​ are

< 4, 5 , 7 >

< 4, - 5 , 7 >

< 4, - 5, - 7 >

< - 4, 5 , 7 >

Correct answer is (a) < 4, 5 , 7 >

Q. The direction ratios of the line which is perpendicular to the lines $\frac{x - 7}{2} = \frac{y + 17}{- 3} = \frac{z - 6}{1}$ and $\frac{x + 5}{1} = \frac{y + 3}{2} = \frac{z - 4}{- 2}$ are