Q.
The direction cosines of a line equally inclined to three mutually perpendicular lines having direction cosines as l1,m1,n1;l2,m2,n2 and l3,m3,n3 are
Since the three lines are mutually perpendicular, ∴l1l2+m1m2+n1n2=0 l2l3+m2m3+n2n3=0 l3l1+m3m1+n3n1=0
Also, l12+m12+n12=1,l22+m22+n22=1, l32+m32+n32=1
Now, (l1+l2+l3)2+(m1+m2+m3)2+(n1+n2+n3)2 =(l12+m12+n12)+(l22+m22+n22) +(l32+m32+n32)+2(l1l2+m1m2+n1n2) +2(l2l3+m2m3+n2n3) +2(l3l1+m3m1+n3n1) =3 ⇒(l1+l2+l3)2+(m1+m2+m3)2 +(n1+n2+n3)2=3
Here, direction cosines of required line are (3l1+l2+l3,3m1+m2+m3,3n1+n2+n3)