The dipole moments of CCl4,CHCl3 and CH4 are in the order

Question

The dipole moments of CCl4,CHCl3 and CH4 are in the order (A) CH4 < CCl4 < CHCl3 (B) CHCl3 < CH4=CCl4 (C) CH4=CCl4 < CHCl3 (D) CCl4 < CH4 < CHCl3

Tardigrade Admin · Accepted Answer

The dipolemoment is zero for certain molecular geometries which are symmetric. Therefore, they will have no dipole even if the bonds are polar. These geometries include linear, trigonal planar, tetrahedral, octahedral and trigonal bipyramid.

CC l_{4}, C H C l_{3}

and

C H_{4}

are in the order

C H_{4} = CC l_{4} < C H C l_{3}

.

Q. The dipole moments of $CC l_{4}, C H C l_{3}$ and $C H_{4}$ are in the order

$C H_{4} < CC l_{4} < C H C l_{3}$

$C H C l_{3} < C H_{4} = CC l_{4}$

$C H_{4} = CC l_{4} < C H C l_{3}$

$CC l_{4} < C H_{4} < C H C l_{3}$

Q. The dipole moments of CCl4​,CHCl3​ and CH4​ are in the order

CH4​<CCl4​<CHCl3​

CHCl3​<CH4​=CCl4​

CH4​=CCl4​<CHCl3​

CCl4​<CH4​<CHCl3​

Q. The dipole moments of $CC l_{4}, C H C l_{3}$ and $C H_{4}$ are in the order

$C H_{4} < CC l_{4} < C H C l_{3}$

$C H C l_{3} < C H_{4} = CC l_{4}$

$C H_{4} = CC l_{4} < C H C l_{3}$

$CC l_{4} < C H_{4} < C H C l_{3}$