The dipole moments of CCl4, CHCl3 and CH4 are in the order :

Question

The dipole moments of CCl4, CHCl3 and CH4 are in the order : (A) CH4 = CCl4 < CHCl3 (B) CHCl3 < CH4 - CCl4 (C) CH4 < CCl4 < CHCl3 (D) CCl4 < CH4 < CHCl3

Tardigrade Admin · Accepted Answer

Correct answer is (a) CH4 = CCl4 < CHCl3

Q. The dipole moments of $CC l_{4}, C H C l_{3}$ and $C H_{4}$ are in the order :

$C H_{4} = CC l_{4} < C H C l_{3}$

$C H C l_{3} < C H_{4} - CC l_{4}$

$C H_{4} < CC l_{4} < C H C l_{3}$

$CC l_{4} < C H_{4} < C H C l_{3}$

Correct answer is (a) $C H_{4} = CC l_{4} < C H C l_{3}$

Q. The dipole moments of CCl4​,CHCl3​ and CH4​ are in the order :

CH4​=CCl4​<CHCl3​

CHCl3​<CH4​−CCl4​

CH4​<CCl4​<CHCl3​

CCl4​<CH4​<CHCl3​

Correct answer is (a) CH4​=CCl4​<CHCl3​

Q. The dipole moments of $CC l_{4}, C H C l_{3}$ and $C H_{4}$ are in the order :

$C H_{4} = CC l_{4} < C H C l_{3}$

$C H C l_{3} < C H_{4} - CC l_{4}$

$C H_{4} < CC l_{4} < C H C l_{3}$

$CC l_{4} < C H_{4} < C H C l_{3}$

Correct answer is (a) $C H_{4} = CC l_{4} < C H C l_{3}$