Question

The dipole moment of $HBr$ is $2.6\times 10^{-30}$ esv.cm and the interatomic spacing is $1.41\mathring{A}$ . The percentage of ionic character in HBr is

• A. 10.5
• B. 11.5
• C. 12.5
• D. 13.5

Answer 1

Answer: (B)

Percentage ionic character $=\frac{\text{ Observed dipole moment }}{\text{ Theoretical dipole moment }}\times 100$
Theoretical dipole moment of a $100\%$ ionic character
$=e\times d=\left(1.6\times 10^{-19}C\right)\times \left(1.41\times 1(0{)}^{-10}m\right)$
$=2.256\times 10^{-29}$
$\%$ ionic character $=\frac{2.6\times 10^{-30}}{2.256\times 6\times 10^{-29}}\times 100=11.5\%$