The dipole moment of HBr is 1.6 × 10-30 C-m and interatomic spacing is 1 mathringA. The per cent ionic character of HBr is

Question

The dipole moment of HBr is 1.6 × 10-30 C-m and interatomic spacing is 1 mathringA. The per cent ionic character of HBr is (A) 7 (B) 10 (C) 15 (D) 27

Tardigrade Admin · Accepted Answer

Charge of electron = 1.6 × 10-19C Dipole moment of HBr = 1.6 × 1.6× -30 Inter-atomic spacing = 1 mathringA = 1 × 10-10 m % ionic character in HBr =(dipole moment of HBr ×100/inter spacing distance × q) =(1.6 ×10-30/1.6 × 10-19 × 10-10)×100 =10-30×1029 ×100 =0.1× 100 =10 %

Q. The dipole moment of HBr is 1.6×10−30C-m and interatomic spacing is 1A˚. The per cent ionic character of HBr is

7

10

15

27

Charge of electron =1.6×10−19C Dipole moment of HBr =1.6×1.6×−30 Inter-atomic spacing =1A˚ =1×10−10m % ionic character in HBr =interspacingdistance×qdipolemomentofHBr×100​ =1.6×10−19×10−101.6×10−30​×100 =10−30×1029×100 =0.1×100 =10%

Q. The dipole moment of HBr is $1.6 \times 1 0^{- 30}$ C-m and interatomic spacing is $1 \overset{˚}{A}$ . The per cent ionic character of HBr is